JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Multinomial Theorem, Number of Divisors, Miscellaneous problems

  • question_answer
    The number of divisors of 9600 including 1 and 9600 are [IIT Screening 1993]

    A) 60

    B) 58

    C) 48

    D) 46

    Correct Answer: C

    Solution :

    Since \[9600={{2}^{7}}\times 3\times {{5}^{2}}\] Hence, number of divisors\[=(7+1)(1+1)(2+1)=48\].


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