JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank Multinomial theorem, Terms free from radical sign in the expansion(a1/p+b1/q), Problems regarding to three four consecutive terms or coefficients

  • question_answer
    The number of terms which are free from radical signs in the expansion of \[{{({{y}^{1/5}}+{{x}^{1/10}})}^{55}}\]is

    A) 5

    B) 6

    C) 7

    D) None of these

    Correct Answer: B

    Solution :

    In the expansion of \[{{({{y}^{1/5}}+{{x}^{1/10}})}^{55}}\], the general term is \[{{T}_{r+1}}={{\,}^{55}}{{C}_{r}}{{({{y}^{1/5}})}^{55-r}}{{({{x}^{1/10}})}^{r}}={{\,}^{55}}{{C}_{r}}.{{y}^{11-r/5}}{{x}^{r/10}}\]. This \[{{T}_{r+1}}\] will be independent of radicals if the exponents \[r/5\] and \[r/10\] are integers, for \[0\le r\le 55\] which is possible only when\[r=0,10,\,20,\,30,\,40,50\]. \ There are six terms viz. \[{{T}_{1}},{{T}_{11}},{{T}_{21}},{{T}_{31}},{{T}_{41}},{{T}_{51}}\] which are independent of radicals.


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