| A. \[\text{5}\times \text{2}\] |
| B. \[2\times 3\] |
| C. \[\text{7}\times \text{2}\] |
| D. \[3\times 5\] |
A) D A B C
B) A D B C
C) A C B D
D) B A C D
Correct Answer: D
Solution :
\[\text{A }=\text{5}\times \text{2}=\text{ 1}0\] \[\text{B}.=\text{2}\times \text{3}=\text{6}\] \[\text{C }=\text{ 7 }\times \text{ 2 }=\text{ 14}\] \[\text{D }=\text{ 3 }\times \text{ 5 }=\text{ 15}\]
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