A) \[\text{6}.0\text{23 }\times \text{ 1}{{0}^{\text{23}}}\text{ g}/\text{mol}\]
B) \[\text{5}.\text{486 }\times \text{ 1}{{0}^{-\text{4}}}\text{ g}/\text{mol}\]
C) \[9.108\times {{10}^{-28}}Kg/mol\]
D) \[\text{9}.\text{1}0\text{8 }\times \text{l}{{0}^{-\text{24}}}\text{ g}/\text{mol}\]
Correct Answer: B
Solution :
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