A) + 3
B) + 5
C) - 3 and + 3
D) + 3 and + 5
Correct Answer: C
Solution :
\[\underset{(\text{Oxidation}\,\text{number})}{\mathop{N{{H}_{4}}N{{O}_{2}}}}\,\] ⇌\[\underset{x=1-4=-3}{\mathop{\underset{x+4=+1}{\mathop{\overset{*}{\mathop{N}}\,H_{4}^{+}}}\,}}\,+\underset{x=+3}{\mathop{\underset{x-4=-1}{\mathop{\overset{*}{\mathop{N}}\,O_{2}^{-}}}\,}}\,\]
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