A) \[{{N}_{2}}O\]
B) \[{{N}_{2}}{{O}_{3}}\]
C) \[{{N}_{2}}{{O}_{4}}\]
D) \[{{N}_{2}}{{O}_{5}}\]
Correct Answer: B
Solution :
\[NO(g)+N{{O}_{2}}(g)\xrightarrow{-30{}^\circ C}\underset{\text{(Blue)}}{\mathop{{{N}_{2}}{{O}_{3}}(l)}}\,\]
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