A) 89
B) 97
C) 101
D) 123
Correct Answer: C
Solution :
The required term is the \[{{11}^{th}}\] term of the series \[1+2+5+10+17+26+37+50+65+82+101+......\] Aliter: \[{{n}^{th}}\] term of the series \[1+2+5+10+17+.......\]is \[{{(n-1)}^{2}}+1\] \[\therefore \]\[{{T}_{11}}={{10}^{2}}+1=101\].
You need to login to perform this action.
You will be redirected in
3 sec
