question_answer

When \[_{3}^{7}\] \[Li\] is bombarded with ascertain particle, two alpha particles are produced. Identify the bombarding particle.                      

Answer:

                Let \[_{Z}^{A}\] P be the bombarding particle. Then \[_{3}^{7}Li+_{Z}^{A}P\to _{2}^{4}He+_{2}^{4}He\] Using the laws of conservation of mass and energy, we get \[A+7=4+4\]       or \[A=1\] \[Z+3=2+2\]       or \[Z=1\] Thus, the bombarding particle is a proton \[(_{1}^{1}H)\].