Use this graph to explain why the force between the nucleons must be regarded as (i) strongly repulsive for separation values less than \[{{r}_{0}}\]. (ii) attractive nuclear force \[(r>{{r}_{0}})\]
Answer:
The potential energy of the two nucleons is minimum at a separation of\[{{r}_{0}}\]. (i) For separation values less than\[{{r}_{0}}\], the P.E. increases rapidly with the decrease in separation r. This indicates strong repulsion between the nucleons. (iii) For separation values greater than \[{{r}_{0}}\] , the P.E. is negative which falls to zero for a separation more than a few femtometers. This indicates an attractive force between the nucleons.
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