A) \[NO_{2}^{+}\]
B) \[N{{O}_{2}}\]
C) \[N{{O}^{+}}\]
D) \[NO_{2}^{-}\]
Correct Answer: A
Solution :
\[NO_{2}^{\oplus }\] is produced when conc.\[HN{{O}_{3}}\] reacts with conc.\[{{H}_{2}}S{{O}_{4}}\]. \[HN{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\to HSO_{4}^{-}+NO_{2}^{\oplus }+{{H}_{2}}O\]
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