question_answer

The maximum velocity of a particle, executing simple harmonic motion with an amplitude of 7 mm, is\[4.4m{{s}^{-1}}\]. What is the period of oscillation?

Answer:

                \[{{\upsilon }_{\max }}=\omega A=\frac{2\pi }{T}A\]                 \[\therefore \]  \[T=\frac{2\pi A}{{{\upsilon }_{\max }}}\]                 \[=\frac{2\times 22\times 7\times {{10}^{-3}}}{7\times 4.4}=\mathbf{0}\mathbf{.01s}.\]