question_answer

The bob of a vibrating pendulum is made of ice. How will the time period change when the ice starts melting?

Answer:

                                        If the ice bob is of very small size, the position of its C.G. will remain same as the ice melts. Hence its time period will remain same. If the size of the ice bob is large, then \[T=2\pi \sqrt{\frac{\frac{2{{r}^{2}}}{5l}+l}{g}}\] As ice melts, the radius r and hence the time period T will decrease. The pendulum will oscillate faster.