A) Reduction
B) Oxidation
C) Hydrolysis
D) Its acidic nature
Correct Answer: A
Solution :
\[\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{ Violet}\,\text{ } \\ \text{ }\text{vapour } \end{smallmatrix}}{\mathop{{{H}_{2}}S{{O}_{4}}+2HI\,\to \,2{{H}_{2}}O+{{I}_{2}}+S{{O}_{2}}}}\,\uparrow \](nascent hydrogen) Coloured flower \[+\,2[H]\to \]Colourless flower
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