A) \[{{R}_{3}}Si-O-Si{{R}_{3}}\]
B) (\[\,{{R}_{3}}Si-O-Si{{R}_{3}}\,\])n
C) \[{{R}_{3}}SiOH\]
D) \[\overset{R\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,R}{\mathop{\overset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}{\mathop{\overset{-Si\,\,-\,O\,\,-Si\,-}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,}{\mathop{\underset{-Si-O-Si-}{\mathop{\underset{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}{\mathop{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}}\,}}\,}}\,}}\,}}\,}}\,\]
Correct Answer: A
Solution :
\[{{R}_{3}}SiCl\] on hydrolysis forms only a dimer. \[{{R}_{3}}SiOH+HOSi{{R}_{3}}\to {{R}_{3}}Si-O-Si{{R}_{3}}\].
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