question_answer

In a parallelogram ABCD, the diagonal AC measures 34 m and the perpendicular distance of AC from either of the vertices B and D is 12 m. Find area of parallelogram.

A)  204sq.m   

B)  408sq.m  

C)  816sq.m   

D)  806sq.m

Correct Answer: B

Solution :

       In   \[\Delta \,\,ABC,\] base \[=AC=34\text{ }m,\] height \[=BM=12\text{ }m\] Area of \[\Delta \,\,ABC=\frac{1}{2}\times 34\times 12\]                                 \[=204\,\,{{m}^{2}}\] Similarly the area of \[\Delta \,\,ADC=204\,{{m}^{2}}\] Area of parallelogram \[=(204++204)\,{{m}^{2}}=408\,{{m}^{2}}\]