A) \[375\,{{m}^{2}}\]
B) \[375\,c{{m}^{2}}\]
C) \[475\,{{m}^{2}}\]
D) \[425\,c{{m}^{2}}\]
Correct Answer: B
Solution :
Consider \[PR=25\text{ }cm\] as the base of two triangles, \[\Delta PQR\] and \[\Delta PSR\]. Area of \[\Delta PQR=\frac{1}{2}\times 25\times 15\] \[=\frac{375}{2}\,c{{m}^{2}}\] Similarly area of \[\Delta \,PSR\,=\frac{1}{2}\times 25\times 15\] \[=\frac{375}{2}\,c{{m}^{2}}\] \[\therefore \] Area of shaded region = Area of rectangle - (area of \[\Delta \,PQR\,+\]area of \[\Delta \,PSR\]) \[=(25\times 15)-\left( \frac{375}{2}+\frac{375}{2} \right)\] \[=750-375\,\,c{{m}^{2}}=375\,c{{m}^{2}}\]
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