A) \[\frac{\pi }{4}\]
B) \[\frac{\pi }{2}\]
C) \[\pi \]
D) \[2\pi \]
Correct Answer: D
Solution :
\[\sin \theta -\sqrt{3}\cos \theta =2\sin \left( \theta -\frac{\pi }{3} \right)\], hence period = \[2\pi \].
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