A) \[\frac{2\pi }{3}\]
B) \[\pi \]
C) \[\frac{\pi }{2}\]
D) \[\frac{\pi }{3}\]
Correct Answer: D
Solution :
Period of \[2\sin 3\theta \] is \[\frac{2\pi }{3}\] and period of \[4\cos 3\theta \] is \[\frac{2\pi }{3}\]. Therefore period of the expression is\[\frac{\pi }{3}\].
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