A) (6, 8)
B) (6, - 8)
C) (3, 4)
D) (- 3, - 4)
Correct Answer: B
Solution :
\[{{x}^{2}}+{{y}^{2}}={{(x+4)}^{2}}+{{(y+8)}^{2}}\,\,\Rightarrow \,\,8x+16y+80=0\] and \[{{x}^{2}}+{{y}^{2}}={{(x+2)}^{2}}+{{(y+2)}^{2}}\,\,\Rightarrow \,\,4x+4y+8=0\] On simplification, we get \[y=-8\] and\[x=6\].
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