A) (7, 9)
B) (9, 7)
C) (-9, 7)
D) (-7, 9)
Correct Answer: A
Solution :
Obviously \[a=11,\,\,b=20,\,\,c=13.\] Hence incentre is \[\left( \frac{11\times 0+20\times 5+13\times 16}{11+20+13},\,\,\frac{11\times 0+20\times 12+13\times 12}{11+20+13} \right)\] i.e. (7, 9)
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