A) Acetone
B) Methyl cyanide
C) Ethylene oxide
D) Ethyl acetate
Correct Answer: C
Solution :
\[\underset{\overset{\,}{\mathop{\overset{\backslash /}{\mathop{O}}\,}}\,\,\,\,}{\mathop{C{{H}_{2}}-C{{H}_{2}}}}\,+C{{H}_{3}}MgI\to \underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,-\underset{OMgI}{\mathop{\underset{|\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,\to \]\[\underset{\text{Propyl alcohol}}{\mathop{\overset{{}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-OH}}\,}}\,+Mg<\begin{matrix} I\,\,\, \\ OH \\ \end{matrix}\]
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