A) Dimethyl ether
B) Diethyl ether
C) Methyl alcohol
D) Ethyl alcohol
Correct Answer: B
Solution :
\[2{{C}_{2}}{{H}_{5}}Br+\underset{\text{Dry}}{\mathop{A{{g}_{2}}O}}\,\to {{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}}+2AgBr\] If we take moist \[A{{g}_{2}}O\] then alcohol is formed \[A{{g}_{2}}O+{{H}_{2}}O\to 2AgOH\] \[{{C}_{2}}{{H}_{5}}Br+AgOH\to {{C}_{2}}{{H}_{5}}OH+AgBr\]
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