A) \[{{({{C}_{2}}{{H}_{5}})}_{3}}CONa+C{{H}_{3}}Cl\]
B) \[{{(C{{H}_{3}})}_{3}}CONa+C{{H}_{3}}Cl\]
C) \[{{(C{{H}_{3}})}_{3}}CONa+{{C}_{2}}{{H}_{5}}Cl\]
D) \[{{(C{{H}_{3}})}_{3}}CONa+C{{H}_{3}}Cl\]
Correct Answer: B
Solution :
\[\underset{\text{2, 2 dimethyl sodium ethoxide}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}\ }{\overset{C{{H}_{3}}\ }{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,-O}}}\,-Na+Cl-C{{H}_{3}}}}\,\to \]\[\underset{\text{Methyl-}t\text{ butyl ether}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}\ }{\overset{C{{H}_{3}}\ }{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,-O}}}\,-C{{H}_{3}}+NaCl}}\,\]
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