A) The ion formed initially may react with \[B{{r}^{-}}\] or \[C{{H}_{3}}OH\]
B) The methyl alcohol solvates the bromine
C) The reaction follows Markownikoff's rule
D) This is a free-radical mechanism
Correct Answer: A
Solution :
\[C{{H}_{2}}=C{{H}_{2}}+B{{r}_{2}}\xrightarrow{C{{H}_{3}}OH}\] \[\underset{Br\,\,\,\,\,}{\mathop{\underset{|}{\mathop{C}}\,{{H}_{2}}-}}\,\underset{Br\,\,\,\,\,\,\,}{\mathop{\underset{|}{\mathop{C}}\,{{H}_{2}}+}}\,Br-C{{H}_{2}}-C{{H}_{2}}-O-C{{H}_{3}}\]
You need to login to perform this action.
You will be redirected in
3 sec
