A) Chloroethane
B) Ethylene dibromide
C) Cyclohexane
D) 1-bromo propane
Correct Answer: B
Solution :
When ethylene reacts with bromine, it forms ethylene dibromide. \[\underset{\text{Ethylene}}{\mathop{{{H}_{2}}C=C{{H}_{2}}}}\,\ +\underset{\text{Bromine}}{\mathop{B{{r}_{2}}}}\,\to \underset{\text{Ethylene dibromide}}{\mathop{{{H}_{2}}\underset{Br\,}{\mathop{\underset{|}{\mathop{C}}\,-}}\,\underset{Br\,\ \ }{\mathop{\underset{|}{\mathop{C}}\,{{H}_{2}}}}\,}}\,\]
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