A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) \[\frac{5}{6}\]
D) \[\frac{3}{5}\]
Correct Answer: C
Solution :
\[\text{E}=\text{ }\!\!\{\!\!\text{ 2},\text{ 3},\text{ 4},\text{ 5},\text{ 6}\}\,\,\Rightarrow \text{ n(E)}=\text{5}\] \[\text{S}=\text{ }\!\!\{\!\!\text{ 1},\text{ 2},\text{ 3},\text{ 4},\text{ 5},\text{ 6}\}\text{ }\Rightarrow \text{ n(S)}=\text{6}\] \[\therefore \]\[p(E)=\frac{n(E)}{n(S)}=\frac{5}{6}\]
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