A) \[6x+y-32=0\]
B) \[6x-y+32=0\]
C) \[x+6y-32=0\]
D) \[6x-y-32=0\]
Correct Answer: A
Solution :
Let the point be \[(x,\,y).\] Area of triangle with points \[(x,\,y),\,(1,\,5)\] and \[(3,\,-7)\] is 21 sq. units \ \[\frac{1}{2}\left| \,\begin{matrix} x & y & 1 \\ 1 & 5 & 1 \\ 3 & -7 & 1 \\ \end{matrix} \right|=21\] Solving; locus of point \[(x,\,y)\] is \[6x+y-32=0\].
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