A) \[{{C}_{2}}{{H}_{5}}OH\] and \[{{C}_{2}}{{H}_{5}}ONa\]
B) \[{{C}_{3}}{{H}_{7}}OH\] and \[C{{H}_{3}}ONa\]
C) \[C{{H}_{3}}OH\] and \[C{{H}_{3}}ONa\]
D) \[{{C}_{4}}{{H}_{9}}OH\] and \[{{C}_{4}}{{H}_{9}}ONa\]
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}OH+Na\to {{C}_{2}}{{H}_{5}}ONa\] \[2{{C}_{2}}{{H}_{5}}OH\underset{{{H}_{2}}S{{O}_{4}}}{\mathop{\xrightarrow{\text{Conc}\text{.}}}}\,{{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}}+{{H}_{2}}O\]
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