A) Chlorine
B) Hydrogen chloride
C) Phosphorus trichloride
D) Phosphorus pentachloride
Correct Answer: A
Solution :
\[C{{H}_{3}}OH+C{{l}_{2}}\to \text{No}\,\,\text{reaction}\] \[C{{H}_{3}}OH+HCl\xrightarrow{ZnC{{l}_{2}}}C{{H}_{3}}Cl+{{H}_{2}}O\] \[3C{{H}_{3}}OH+PC{{l}_{3}}\to 3C{{H}_{3}}Cl+{{H}_{3}}P{{O}_{3}}\] \[C{{H}_{3}}OH+PC{{l}_{5}}\to C{{H}_{3}}Cl+POC{{l}_{3}}+HCl\]
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