A) \[{{H}_{2}}O,\ {{H}_{2}}S{{O}_{4}}\]
B) Aqueous \[KOH\]
C) \[MgS{{O}_{4}},\ NaB{{H}_{4}}/{{H}_{2}}O\]
D) \[{{B}_{2}}{{H}_{6}},\ {{H}_{2}}{{O}_{2}},\ O{{H}^{-}}\]
Correct Answer: B
Solution :
\[\underset{\text{Propene}-\text{1}}{\mathop{C{{H}_{3}}-CH=C{{H}_{2}}}}\,+aq.\,KOH\to \underset{\text{Propanol}\,-\,\text{1}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH}}\,\]
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