A) \[O{{H}^{-}}\] is replaced by \[C{{H}_{3}}COO\] group
B) \[O{{H}^{-}}\] is replaced by chlorine
C) \[{{H}^{-}}\] is replaced by sodium metal
D) \[O{{H}^{-}}\]is replaced by \[{{C}_{2}}{{H}_{5}}OH\]
Correct Answer: A
Solution :
\[C{{H}_{3}}COOH+{{C}_{2}}{{H}_{5}}OH\to \underset{\text{Ethyl}\,\,\text{acetate}}{\mathop{C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}}}\,+{{H}_{2}}O\]
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