A) \[{{H}_{3}}C-C{{H}_{2}}-C{{H}_{2}}OH\]
B) \[\underset{\underset{OH}{\mathop{|}}\,}{\mathop{C{{H}_{3}}-CH-C{{H}_{3}}}}\,\]
C) \[\begin{matrix} C{{H}_{3}} & - & {} & {} & {} \\ C{{H}_{3}} & > & C & - & OH \\ C{{H}_{3}} & {} & {} & {} & {} \\ \end{matrix}\]
D) \[C{{H}_{2}}=CH-C{{H}_{2}}OH\]
Correct Answer: B
Solution :
Secondary alcohol on dehydrogenation gives acetone \[C{{H}_{3}}-\underset{\underset{OH}{\mathop{|\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{3}}\underset{{{300}^{0}}C}{\mathop{\xrightarrow{Cu}}}\,\,C{{H}_{3}}-\underset{\underset{O}{\mathop{||}}\,}{\mathop{C}}\,-C{{H}_{3}}+{{H}_{2}}\]
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