A) \[\overset{\overset{\,\,O}{\mathop{\,\,\,||}}\,}{\mathop{{{C}_{6}}{{H}_{5}}CC{{H}_{3}}}}\,\underset{2.{{H}^{+}}}{\mathop{\xrightarrow{1.C{{H}_{3}}MgBr}}}\,\]
B) \[\overset{\overset{\,\,O}{\mathop{\,\,\,||}}\,}{\mathop{{{C}_{6}}{{H}_{5}}CC{{H}_{3}}}}\,\underset{2.{{H}^{+}}}{\mathop{\xrightarrow{1.LiAl{{H}_{4}}}}}\,\]
C) \[C{{H}_{3}}CHO\underset{2.{{H}^{+}}}{\mathop{\xrightarrow{1.LiAl{{H}_{4}}}}}\,\]
D) \[\overset{\overset{O}{\mathop{||}}\,}{\mathop{C{{H}_{3}}CC{{H}_{3}}}}\,\underset{2.B{{r}_{2}}}{\mathop{\xrightarrow{1.O{{H}^{-}}}}}\,\]
Correct Answer: B
Solution :
\[\underset{\text{Acetophenone}}{\mathop{{{C}_{6}}{{H}_{5}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\xrightarrow{LiAl{{H}_{4}}}\]\[\underset{\,{{2}^{o}}\,\,\text{alcohol}}{\mathop{{{C}_{6}}{{H}_{5}}-\overset{O\,\,}{\mathop{\overset{||\,\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{3}}}}\,\]
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