A) \[\frac{{{2}^{n}}}{n+1}\]
B) \[\frac{{{2}^{n}}-1}{n+1}\]
C) \[\frac{{{2}^{n+1}}-1}{n+1}\]
D) None of these
Correct Answer: C
Solution :
Proceeding as above and putting n+1=N. So given term can be written as \[\frac{1}{N}\left\{ {{\,}^{N}}{{C}_{1}}+{{\,}^{N}}{{C}_{2}}+{{\,}^{N}}{{C}_{3}}+.... \right\}\] = \[\frac{1}{N}\left\{ {{2}^{N}}-1 \right\}=\frac{1}{n+1}({{2}^{n+1}}-1)\] \[(\because N=n+1)\]
You need to login to perform this action.
You will be redirected in
3 sec
