A) \[C{{H}_{3}}COONa\]
B) \[HCOONa\]
C) Sodium oxalate
D) \[C{{H}_{3}}OH\]
Correct Answer: B
Solution :
\[CHC{{l}_{3}}+3NaOH\xrightarrow[-3HCl]{}CH<-\begin{matrix} OH \\ OH \\ OH \\ \end{matrix}\xrightarrow[-{{H}_{2}}O]{}\]\[HCOOH\underset{-{{H}_{2}}O}{\mathop{\xrightarrow{NaOH}}}\,HCOONa\]
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