A) \[{{C}_{6}}{{H}_{5}}CON{{H}_{2}}\]
B) \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\]
C) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}NHC{{H}_{3}}\]
D) \[{{C}_{6}}{{H}_{5}}NHC{{H}_{3}}\]
Correct Answer: B
Solution :
\[\underset{X}{\mathop{\underset{\,\text{(Aniline)}}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,}}\,+CHC{{l}_{3}}+3NaOH\to \] \[3NaCl+3{{H}_{2}}O+\underset{\text{Phenyl}\,\,\text{isocyanide}}{\mathop{{{C}_{6}}{{H}_{5}}-N\vec{=}\,C}}\,\]
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