A) Propan - 2 - ol
B) Propan - l - ol
C) Propyne
D) Propene
Correct Answer: A
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-Br\xrightarrow{\text{alc}\text{.}\,\,KOH}\underset{\text{(A)}}{\mathop{C{{H}_{3}}-CH=C{{H}_{2}}}}\,\] \[\underset{\text{Propan-2-ol}}{\mathop{\begin{array}{*{35}{l}} C{{H}_{3}}-CH-C{{H}_{3}}\xleftarrow{aq.\,KOH} \\ \,\,\,\,\,\,\,\,\,\,\,\overset{|\,\,\,}{\mathop{\,\,OH}}\, \\ \end{array}}}\,\begin{array}{*{35}{l}} C{{H}_{3}}-CH-C{{H}_{3}} \\ \,\,\,\,\,\,\,\,\,\,\,\overset{|\,\,\,}{\mathop{\,\,Br}}\, \\ \end{array}\]
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