| Seven children A, B, C, D, E, F and G are standing in a line. G is to the right to D and to the left of B. A is on the right of C. A and D have one child between them. E and B have two children between them. |
A) A
B) B
C) C
D) D
Correct Answer: C
Solution :
C is on the extreme left. (10 to 12) L is at the right of M and at third place at the right of N. So, the sequence becomes: N \[\square \] M L. O is at third place at the left of K and J is right next to left of 0 i.e., JO \[\square \]\[\square \] K. Q is adjacent to both 0 and P i.e., J O Q P K. Thus, the only black space left must be occupied by R i.e., NRML. Since K is at one end of the row, so the entire seating sequence becomes: NRMUOQPK.
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