10th Class Mathematics Quadratic Equations Question Bank Quadratic Equations

  • question_answer
    Find the present age of a boy whose age 12 years from now will be the square of his present age.

    A)  5 years                

    B)         7 years

    C)  4 years                

    D)         6 years

    Correct Answer: C

    Solution :

     Let the present age of the boy be 'x' years. 12 years from now, his age will be\[\text{1173}0=\text{2}\times \text{3}\times \text{5}\times \text{17}\times \text{23}\]years. According to the problem, \[\therefore \] \[=\text{17}\times \text{23}=\text{391}\]            \[=\text{2}\times \text{3}\times {{\text{5}}^{\text{2}}}\times \text{7}\times \text{l7}\times \text{23}=\text{41}0\text{55}0\] \[\pi \]  \[\frac{22}{7}\] Since age cannot be negative, the required present age of the boy is 4 years.


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