A) 1
B) 0.5
C) 2
D) 0.05
Correct Answer: A
Solution :
\[{{C}_{6}}{{H}_{12}}{{O}_{6}}+6{{O}_{2}}\xrightarrow{{}}6C{{O}_{2}}+6{{H}_{2}}O\] \[\text{R}\text{.Q}\text{.}=\frac{\text{Vol}\text{.}\,\text{of}\,C{{O}_{2}}}{\text{Vol}\,\text{of}\,{{O}_{2}}}=\frac{6}{6}=1\]
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