question_answer

A lens whose radii of curvature are different is forming the image of an object placed on its axis. If the lens is placed with its faces reversed, will the position of the image change?

Answer:

                No, the image will be formed at the same position. From lens maker's formula,      \[\frac{1}{f}=(\mu -1)\left[ \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right],\] it is clear that when we interchange \[{{R}_{1}}\] and \[{{R}_{2}}\], the magnitude of \[f\] remains the same.