Answer:
Linear magnification produced by an optical instrument is the ratio of the size of the image to the size of the object. It is equal to the ratio of the image distance and the object distance. \[\therefore \] Linear magnification \[=\frac{{{h}_{2}}}{{{h}_{1}}}=\frac{\upsilon }{u}\] The angular magnification or magnifying power of an optical instrument is the ratio of angle subtended by the image at the eye to the angle subtended by the object seen directly, when both lie at the least distance of distinct vision. \[\therefore \] Angular magnification \[=\frac{\beta }{\alpha }=\frac{D}{u}\] The linear and angular magnifications will become equal when Image distance \[(\upsilon )=\]The least distance of distinct vision (D).
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