A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: D
Solution :
\[a,\ b,\ c\] be in A.P. then divide each term by \[bc\], we get \[\frac{a}{bc},\ \frac{1}{c},\ \frac{1}{b}\] be in A.P. But it is \[\frac{2}{b}\] in place of \[\frac{1}{b}\], so answer is (d).
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