A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: B
Solution :
As given \[2b=a+c\] \[\Rightarrow {{3}^{2b}}={{3}^{a+c}}\] or \[{{({{3}^{b}})}^{2}}={{3}^{a}}.\ {{3}^{c}}\ i.e.\ {{3}^{a}},\ {{3}^{b}},\ {{3}^{c}}\] are in G.P. Note: Students should remember this question as a fact.
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