A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: C
Solution :
If \[a,\ b,\ c\] are in H.P. \[\frac{1}{a}+\frac{1}{c}=\frac{2}{b}\] are also in A.P. \[\Rightarrow \] \[\frac{a+b+c}{a},\ \frac{a+b+c}{b},\ \frac{a+b+c}{c}\] are in A.P. \[\Rightarrow \] \[\frac{b+c}{a},\ \frac{a+c}{b},\ \frac{a+b}{c}\]are in A.P. \[\Rightarrow \] \[\frac{a}{b+c},\ \frac{b}{a+c},\ \frac{c}{a+b}\] are in H.P.
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