A) \[-\frac{3}{7}\]
B) \[\frac{3}{7}\]
C) \[-\frac{3}{5}\]
D) \[\frac{3}{5}\]
Correct Answer: A
Solution :
Given equation \[4{{x}^{2}}+3x+7=0\], therefore \[\alpha +\beta =-\frac{3}{4}\] and \[\alpha \beta =\frac{7}{4}\] Now\[\frac{1}{\alpha }+\frac{1}{\beta }=\frac{\alpha +\beta }{\alpha \beta }=\frac{-3/4}{7/4}=\frac{-3}{4}\times \frac{4}{7}=-\frac{3}{7}\].You need to login to perform this action.
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