A) \[a-c=0\]
B) \[b-c=0\]
C) \[a+c=0\]
D) \[b+c=0\]
Correct Answer: A
Solution :
Given equation is \[a{{x}^{2}}+bx+c=0\]and whose roots are \[\alpha \]and \[\frac{1}{\alpha }\], then the product of roots is \[\alpha .\frac{1}{\alpha }=\frac{c}{a}\Rightarrow c=a\Rightarrow a-c=0\]
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