A) \[7{{x}^{2}}-6x+1=0\]
B) \[6{{x}^{2}}-7x+1=0\]
C) \[{{x}^{2}}-6x+7=0\]
D) \[{{x}^{2}}-7x+6=0\]
Correct Answer: A
Solution :
The required equation is \[{{x}^{2}}-\left( \frac{1}{3+\sqrt{2}}+\frac{1}{3-\sqrt{2}} \right)x+\frac{1}{3+\sqrt{2}}\times \frac{1}{3-\sqrt{2}}=0\] \[\Rightarrow {{x}^{2}}-\left( \frac{6}{7} \right)x+\frac{1}{7}=0\Rightarrow 7{{x}^{2}}-6x+1=0\]
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