A) \[{{b}^{2}}-4ac\]
B) \[{{b}^{2}}-2ac\]
C) \[2{{b}^{2}}-ac\]
D) None of these
Correct Answer: A
Solution :
Here \[\frac{\alpha +1}{\alpha }+\frac{\alpha }{\alpha -1}=-\frac{b}{a}\]and \[\frac{\alpha +1}{\alpha -1}=\frac{c}{a}\] \\[\alpha =\frac{c+a}{c-a}\]and \[\frac{2{{\alpha }^{2}}-1}{\alpha (\alpha -1)}=-\frac{b}{a}\] Substituting\[\alpha \], we get \[{{(a+b+c)}^{2}}={{b}^{2}}-4ac\]. Note: Students should remember this fact.
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