A) 16
B) 32
C) 64
D) None of these
Correct Answer: B
Solution :
Here \[{{\alpha }^{2}}+{{\beta }^{2}}=-4,{{\alpha }^{3}}+{{\beta }^{3}}=-16\] \\[({{\alpha }^{2}}+{{\beta }^{2}})({{\alpha }^{3}}+{{\beta }^{3}})={{\alpha }^{5}}+{{\beta }^{5}}+{{\alpha }^{2}}{{\beta }^{2}}(\alpha +\beta )\] Þ \[(-4)(-16)={{\alpha }^{5}}+{{\beta }^{5}}+(16)(2)\]Þ\[{{\alpha }^{5}}+{{\beta }^{5}}=32\]
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